How did you get on with the last question? Bit tricky? Here are my thoughts.
June 03 Dale bay at 1630 draught is 3m
HW 1533 6.2m LW 2155 1.4m - it is June so add 1 hr to bring tide times to BST
| What is the height of tide at 1630 | Arriving at HW - 3 minutes - it will be virtually HW 6.2m |
| How much will the tide fall between 1630 and LW | Tidal range is 6.2 - 1.4 = 4.8m |
| What is the depth of water to anchor in at 1630 to allow a clearance of 2 metres at LW |
Draught is 3m need a clearance of 2m = 5m
LW is 1.4m , need 5m - 1.4m = 3.6m
HW is 6.2m add 3.6m (range) = 9.8m
|
June 18 1530 anchoring - draught 1.9m
HW 1536 5.6m LW 2152 2.0m. it is June so add 1 hr to bring tide times to BST
| What is the height of the tide at 1535 |
Arrive at HW - 1hr
HW 5.6m LW 2.0m range = 3.6m
1/12 is 0.3m 10 % is 0.36m
HOT at HW - 1hr is
5.3m if you used the rule of 12th’s
5.24m if you used the % rule
Let’s use 5.3m
|
| How much will the tide fall between 1535 and LW |
Arrival depth is 5.3m LW is 2.0m
5.3 - 2.0 = 3.3m
|
| What is the depth of water to anchor in at 1535 to allow a 1 metre clearance at LW |
HW 5.6m LW 2.0m range for the calculation = 3.6m
Draught is 1.9m need a clearance of 1m = 2.9m
LW is 2.0m
2.9 - 2.0 = 0.9m
HOT at 1535 is 5.3m
5.3m + 0.9m = 6.2m
|
If you managed to get all that, very well done...... Reward yourself with tea and cake.